A team adds 5.00 mL of exhibit water to an empty beaker using a volumetric pipette. What is the density of the exhibit water if the empty beaker weighed 18.926g and the beaker weighed 24.041g after adding the water sample?

d = 1.023 g/mL

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Volume of water = 5.00 mL

Weight of empty beaker = 18.926 g

Weight of beaker with water = 24.041 g

Density of water = ?

Solution:

First of all we will calculate the mass of water.

Mass of water = mass of beaker with water - mass of beaker

Mass of water = 24.041 g - 18.926 g

Mass of water = 5.115 g

Density:

d = m/v

d = 5.115 g/ 5.00 mL

d = 1.023 g/mL

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

b. examine and describe cells