White wines tend to be more acidic than red wines. Find the [H3O ] in a Sauvignon Blanc with a pH of 3.23 and a Cabernet Sauvignon with a pH of 3.64. How many times more acidic is the Sauvignon Blanc

The answers are:

[H3O] Sauvignon Blanc = 0.000588

[H3O] Cabernet Sauvignon = 0.000229

Sauvignon Blanc is 2.57 times more acid  than Cabernet Sauvignon

Explanation:

The pH is a measure to calculate the degree of alkalinity or acidity of a solution. Knowing the pH we can calculate the hydrogenation concentration of the two wines. We have to clear the equation:

pH = -log [H3O]

[H3O] = 10^-pH

Replacing we have:

[H3O] Sauvignon Blanc = 10^-3.23 = 0.000588

[H3O] Cabernet Sauvignon = 10^-3.64 = 0.000229

To calculate how many times the Sauvignon Blanc is more acidic than the Cabernet Sauvignon, we just have to divide both hydrogen concentrations, as follows:

0.000588/0.000229 = 2.57 times more acid

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

it takes on an electronical energy