A metal with a specific heat of 0.70 J/gºC and a mass of
8.00 g absorbs 48.0 J of heat. What will be the
temperature change of the metal?
much heat is needed to raise the temnerature of
U

ΔT = 8.6 °C

Explanation:

Given data:

Specific heat of metal = 0.70 j/g.°C

Mass of metal = 8.00 g

Heat absorbed = 48.0 J

Change of temperature = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = m.c. ΔT

48.0 J = 0.70 j/g.°C × 8.00 g ×  ΔT

48.0 J = 5.6  j/°C × ΔT

ΔT = 48.0 J / 5.6  j/°C

ΔT = 8.6 °C

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