9) 1.5 moles of certain gas in a container occupies a volume of 0.25 liters. If 0.5 moles of the gas are added to the container,
calculate the new volume the gas will occupy. During the process, pressure and temperature were kept constant.

0.33L

Explanation:

From ideal gas equation,

PV = nRT

V = nRT/P

If RT/P are kept constant, then:

V1/n1 = V2 /n2

n1 = 1.5moles

V1 = 0.25L

n2 = 1.5 + 0.5 = 2moles

V2 =?

Now, the new volume can be obtain as follows:

V1/n1 = V2 /n2

0.25/1.5 = V2/2

Cross multiply to express in linear form

1.5 x V2 = 0.25 x 2

Divide both side by 1.5

V2 = (0.25 x 2)/1.5

V2 = 0.33L

Therefore, the new volume is 0.33L