Determine the volume of hexane that contains 5.33 × 1022 molecules of hexane. The density of hexane is 0.6548 g/mL and its molar mass is 86.17 g/mol. Determine the volume of hexane that contains 5.33 × 1022 molecules of hexane. The density of hexane is 0.6548 g/mL and its molar mass is 86.17 g/mol. 13.5 mL 11.6 mL 7.40 mL 8.59 mL 12.4 mL

11.6 mL is the volume for 5.33 × 10²² molecules of hexane

Explanation:

We analyse data:

5.33 × 10²² molecules of hexane

0.6548 g/mL

86.17 g/mol

First of all, we determine the moles of hexane that contain 5.33 × 10²² molecules

6.02×10²³ molecules are contained in 1 mol

5.33 × 10²² molecules must be contained in (5.33 × 10²² . 1) / NA = 0.088 moles

Now we convert the moles to mass → 0.088 mol . 86.17 g/m = 7.63 g

Finally we apply density to determine the volume

Density = mass / volume → Volume = Mass / Density

Volume = 7.63 g / 0.6548 g/mL = 11.6 mL

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.