Chemistry, 04.03.2020 23:17 jayleneeurich
A 0.10 M imidazole solution has a pH of 6.6. To the nearest hundredth of a unit, what fraction of the molecules are in the neutral (imidazole) form? (The pKa of the imidazolium ion is 6.0.)
Answers: 3
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](/tpl/images/0533/8426/e961a.png)
![pH=pK_a+\log \frac{[\text{Imidazole}]}{[\text{Imidazolium ion}]}](/tpl/images/0533/8426/c2e7e.png)
![6.6=6.0+\log \frac{[\text{Imidazole}]}{[\text{Imidazolium ion}]}](/tpl/images/0533/8426/895b0.png)
![\frac{[\text{Imidazole}]}{[\text{Imidazolium ion}]}=10^{6.6-6.0}](/tpl/images/0533/8426/0952e.png)
![\frac{[\text{Imidazole}]}{[\text{Imidazolium ion}]}=10^{0.6}](/tpl/images/0533/8426/2864b.png)
![\frac{[\text{Imidazole}]}{[\text{Imidazolium ion}]}=3.98](/tpl/images/0533/8426/0af59.png)
![[\text{Imidazole}]=3.98[\text{Imidazolium ion}]](/tpl/images/0533/8426/f647e.png)
...........(1)![\frac{[\text{Imidazole}]}{[\text{Imidazole}]+[\text{Imidazolium ion}]}](/tpl/images/0533/8426/affc2.png)
![\frac{3.98[\text{Imidazolium ion}]}{3.98[\text{Imidazolium ion}]+[\text{Imidazolium ion}]}](/tpl/images/0533/8426/250f9.png)
![\frac{3.98[\text{Imidazolium ion}]}{4.98[\text{Imidazolium ion}]}](/tpl/images/0533/8426/6749d.png)
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A 0.10 M imidazole solution has a pH of 6.6. To the nearest hundredth of a unit, what fraction of th...
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