How many moles of O2 are produced from the decomposition of 327g of KCIO3

Explanation:

Potassium chlorate

KClO

3

decomposes to produce potassium chloride

KCl

and oxygen

O

2

. Balancing the equation

KClO

3

→

KCl

+

O

2

(not balanced)

based on the fact that the number of moles of oxygen atoms should be the same on both side of the equation will give

KClO

3

→

KCl

+

3

2

O

2

2

KClO

3

→

2

KCl

+

3

O

2

Hence the ratio of number of moles of particles

n

(

O

2

)

n

(

KClO

3

)

=

3

2

n

(

O

2

)

=

n

(

KClO

3

)

⋅

n

(

O

2

)

n

(

KClO

3

)

=

3

2

⋅

n

(

KClO

3

)

Therefore the decomposition of

6.0

l

mol

of

KClO

3

would yield

6.0

⋅

n

(

O

2

)

n

(

KClO

3

)

=

6.0

⋅

3

2

=

9.0

l

mol

Note that the species

KCl

is highly stable. Both the potassium cation

K

+

and the chloride anion

Cl

−

have attained a noble gas octet configuration of valence shell electrons. Chemical reactions tend to favor the most chemically stable combination. Therefore this decomposition reaction would eventually produce

KCl

rather than other salts that contain oxygen.

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the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.