The combustion of ethane ( C 2 H 6 ) produces carbon dioxide and steam. 2 C 2 H 6 ( g ) + 7 O 2 ( g ) ⟶ 4 CO 2 ( g ) + 6 H 2 O ( g ) How many moles of CO 2 are produced when 5.30 mol of ethane is burned in an excess of oxygen?

10.6 moles of CO₂ are produced in this combustion

Explanation:

The combustion reaction is:

2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (g)

We assume the ethane as the limiting reactant because the excersise states that the O₂ is in excess.

We make a rule of three:

2 moles of ethane can produce 4 moles of CO₂

Therefore 5.30 moles of ethane will produce (5.3 . 4) /2 = 10.6 moles

i dont know the answe

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but