You will begin by diluting 5.00 mL of a 0.8 M oxalic acid stock solution with water to a final volume of 100.00 mL. What will be the final concentration of the oxalic acid

0.04M

Explanation:

The following were obtained from the question:

C1 = 0.8M

V1 = 5mL

V2 = 100mL

C2 =?

The final concentration of the diluted solution can be obtained by doing the following:

C1V1 = C2V2

0.8 x 5 = C2 x 100

Divide both side by 100

C2 = (0.8 x 5) /100

C2 = 0.04M

The concentration of the diluted solution is 0.04M