The aurora is caused when electrons and protons, moving in the earth's magnetic field of ≈5×10−5 t, collide with molecules of the atmosphere and cause them to glow. what is the radius of the circular orbit for (a) an electron with speed 1.0×106m/s and (b) a proton with speed 7.0×104m/s. what is re in meters and what is rp in meters?

a) 0.114 meters is the radius of the circular orbit for an electron with given speed.

b) 14.6 meters is the radius of the circular orbit for a proton with given speed.

Explanation:

Force on the charge particle :

Since, the particle is revolving around in a circular path ;

particle in constantly moving in circular path under action of magnetic field:

F = F'

Where :

r = radius of the circular path

m = mass of the particle

v = velocity of the particle

B = magnetic field

q = magnitude of  charge on the particle

a)  Velocity of the electron =  

Mass of electron = m =

Charge on an electron , q=

B =

Radius of the circular orbit for an electron with given speed =

0.114 meters is the radius of the circular orbit for an electron with given speed.

b)  Velocity of the proton =  

Mass of electron = m =

Charge on an electron , q=

B =

Radius of the circular orbit for a proton with given speed =

14.6 meters is the radius of the circular orbit for a proton with given speed.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :