What is the pH of a 6.2 x 10-5 M HCI solution

4.21

Explanation:

First, let us generate the dissociation equation. This is illustrated below:

HCl <==> H^+ + Cl^-

From the equation, 1mole of HCl produced 1mole of H^+. This means that 6.2 x 10^-5M will also produce 6.2 x 10^-5M of H^+.

Now we can calculate the pH of the solution as follows:

[H^+] = 6.2 x 10^-5M

pH = —Log [H^+]

PH = —Log 6.2 x 10^-5

pH = 4.21

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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