The data below were collected for the following reaction at 500 ∘C: CH3CN(g)→CH3NC(g) Time (h) [CH3CN] (M) 0.0 1.000 5.0 0.794 10.0 0.631 15.0 0.501 20.0 0.398 25.0 0.316 what is the half-life for this reaction (at the initial concentration)? answers

Half life = 15hours

Explanation:

CH3CN(g)→CH3NC(g)

Time (h) [CH3CN] (M)

0.0 1.000

5.0 0.794

10.0 0.631

15.0 0.501

20.0 0.398

25.0 0.316

Half life for this reaction?

Half-life is the time required for a quantity to reduce to half of its initial value.

So we just need to look up the values in the table and find how much time for the intial concentation to be reduced to half of its initail value.

From the table, it took 15 hours for the inital concentration (1.0) to be halved (0.501).

Half life = 15hours

is there multiple choice answers?

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.