When methane (CH4) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reaction iCH4(g)+O2(g)→CO2(g)+H2O(g)This type of reaction is referred to as a complete combustion reaction. A)What mass of carbon dioxide is produced from the complete combustion of 1.10×10−3 g of methane?Express your answer with the appropriate units. B)What mass of water is produced from the complete combustion of 1.10×10−3 g of methane?Express your answer with the appropriate units. C)What mass of oxygen is needed for the complete combustion of 1.10×10−3 g of methane?Express your answer with the appropriate units.

For A: The mass of carbon dioxide produced is 0.00303 grams.

For B: The mass of water produced is 0.0025 grams.

For C: The mass of oxygen gas produced is 0.0044 grams.

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of methane =

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

The chemical equation for the combustion of methane follows:

By Stoichiometry of the reaction:

1 mole of methane produces 1 mole of carbon dioxide

So, of methane will produce = of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = moles

Putting values in equation 1, we get:

Hence, the mass of carbon dioxide produced is 0.00303 grams.

By Stoichiometry of the reaction:

1 mole of methane produces 2 moles of water

So, of methane will produce = of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = moles

Putting values in equation 1, we get:

Hence, the mass of water produced is 0.0025 grams.

By Stoichiometry of the reaction:

1 mole of methane reacts with 2 moles of oxygen gas

So, of methane will react with = of oxygen gas

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Moles of oxygen gas = moles

Putting values in equation 1, we get:

Hence, the mass of oxygen gas produced is 0.0044 grams.

passing a magnet thought the

mixture , because iron gets attracted to magnet .

the answer for sodium is 0.186

the answer for rubidium is 0.251