Use the value of the activation energy (Ea=1.50×102kJ/mol) and the given rate constant of the reaction at either of the two temperatures to predict the rate constant at 551 K.

The rate constant

K= 0.967m-1s-1

Explanation: To calculate the rate constant, we will use the Arrhenius equation.

lnK = (- Ea/R) (1/T) + lnZ(1)

K is the rate constant

Ea is the activation energy

R is the gas constant

T is the temperature in Kelvin

Z is the constant related to the geometry needed, but in this question Z is equal to zero.

Therefore fro data given, we have

Ea = 1.50 × 102kj/mol = 153kj/mol

R = 8.314j/mol-k

T = 551k

Z= 0

Therefore using the equation

lnK = -153÷ (8.314 × 551) = -153 × 4581.014

lnK = - 0.033398719

Taking the ln inverse of K

K = e^ (-0.033398819) = 0.96715286

K= 0.967m-1s-1

This is the rate constant

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

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