Before any reaction occurs, the concentrations of A and B in the reaction below are each 0.03900 M . What is the equilibrium constant if the concentration of A at equilibrium is 0.01365 M ? 2A(aq)+B(aq)⇌2C(aq) Round your answer to one decimal place.

Explanation:

As the given reaction is as follows.

Initial:    0.039         0.039                0

Equilbm: 0.01365   0.02535         0.02535

Now, expression for of the given reaction is as follows.

Putting the given values into the above formula as follows.

                      =

                      = 136

Thus, we can conclude that the equilibrium constant for the given reaction is 136.

did you find the answer?

i think its 5049.

i hope this !