Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) Kp = 0.23 at a certain temp If a sample of NaHCO3 is placed in an evacuated flask and allowed to achieve equilibrium, what will the pressure of CO2(g) be?

The pressure of CO2 = 0.48 atm

Explanation:

Step 1: Data given

Kp = 0.23

Step 2: The balanced equation

2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)

Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

Kp = 0.23 = x*x

x = √0.23

x = 0.48

pCO2 = x atm = 0.48 atm

The pressure of CO2 = 0.48 atm

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

the answer is minerals.