Problem 1: 1.85atmProblem 2: 110mLProblem 3: 290 mLProblem 4: 1.14 atm
Explanation:
Problem 1
1. Data
a) P₁ = 3.25atm
b) V₁ = 755mL
c) P₂ = ?
d) V₂ = 1325 mL
r) T = 65ºC
2. Formula
Since the temeperature is constant you can use Boyle's law for idial gases:
3. Solution
Solve, substitute and compute:
Problem 2
1. Data
a) V₁ = 125 mL
b) P₁ = 548mmHg
c) P₁ = 625mmHg
d) V₂ = ?
2. Formula
You assume that the temperature does not change, and then can use Boyl'es law again.
3. Solution
This time, solve for V₂:
Substitute and compute:
You must round to 3 significant figures:
Problem 3
1. Data
a) V₁ = 285mL
b) T₁ = 25ºC
c) V₂ = ?
d) T₂ = 35ºC
2. Formula
At constant pressure, Charle's law states that volume and temperature are inversely related:
The temperatures must be in absolute scale.
3. Solution
a) Convert the temperatures to kelvins:
T₁ = 25 + 273.15K = 298.15KT₂ = 35 + 273.15K = 308.15K
b) Substitute in the formula, solve for V₂, and compute:
You must round to two significant figures: 290 ml
Problem 4
1. Data
a) P = 865mmHg
b) Convert to atm
2. Formula
You must use a conversion factor.
1 atm = 760 mmHg
Divide both sides by 760 mmHg
3. Solution
Multiply 865 mmHg by the conversion factor: