How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation: Q=mc Delta T

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)

Explanation:

Given:

Specific Heat capacity of Iron= 0.450 J/ g °C

To Find:

Required Energy to raise the Temperature

Formula:

Amount of energy required is given by the formula,

Q = mC (ΔT)

Solution:

M = mass of the iron in g

So 3 kg = 3000 g

C = specific heat of iron = 0.450 J/ g °C [ from the given table]

ΔT = change in temperature = 25° C - 20°C = 5°C

Plugin the values, we will get,

Q = 3000 g ×  0.450 J/ g °C ×  5°C

 = 6,750 J

So the energy required is 6,750 J.

the answer is b. dilution