Chemistry, 09.03.2020 16:59 BigDough9090

375 mL of a 0.88 M potassium hydroxide solution is added to 496 mL of a 0.76 M cesium hydroxide solution. Calculate the pOH of the resulting solution.

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Answer from: noahrdavila1978

pOH of resulting solution is 0.086

Explanation:

KOH and CsOH are monoacidic strong base

Number of moles of $OH^{-}$ in 375 mL of 0.88 M of KOH = $\frac{0.88\times 375}{1000}moles$ = 0.33 moles

Number of moles of $OH^{-}$ in 496 mL of 0.76 M of CsOH = $\frac{0.76\times 496}{1000}moles$ = 0.38 moles

Total volume of mixture = (375 + 496) mL = 871 mL

Total number of moles of $OH^{-}$ in mixture = (0.33 + 0.38) moles = 0.71 moles

So, concentration of $OH^{-}$ in mixture, $[OH^{-}]$ = $\frac{0.71}{871}\times 1000M=0.82M$

Hence, $pOH=-log[OH^{-}]=-log(0.82)=0.086$

Answer from: Quest

a mercury barometer is a device that uses the physical properties of mercury in a tube to measure barometric pressure. mercury barometers are used for : -

1. measurement of atmospheric pressure

2. determining the altitude of a place

3. weather forecasting

4. calibration and checking of aneroid barometers

5. application in fluid mechanics

6. measurement of pressure in aircrafts

7. surface weather analysis

8. preparation of barographs

9. usage in physical sciences like physics, astronomy & chemistry

10. preparation of aircraft altimeters

characteristics of mercury barometer : -

1.used to define and measure atmospheric pressure.

2.on the average at sea level the column of mercury rises to a height of about 760 mm.

3.this quantity is equal to 1 atmosphere.

4.it is also known as standard atmospheric pressure.

5.a barometer in which the weight of a column of mercury in a glass tube with a sealed top is balanced against that of the atmosphere pressing on an exposed cistern of mercury at the base of the mercury column, the height of the column varying with atmospheric pressure.

Write 15 uses of a mercury barometer along with its characterestics

Answer from: Quest

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally

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