A sample of N2O effuses from a container in 47 seconds. How long would it take the same amount of gaseous I2 to effuse from the same container under identical conditions

The amount of time required by iodine gas to effuse is 112.9 seconds.

Explanation:

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

So,

We are given:

Moles of iodine gas = Moles of nitrous oxide gas

Time taken by nitrous oxide gas = 47 seconds

Molar mass of iodine gas = 254 g/mol

Molar mass of nitrous oxide gas = 44 g/mol

Putting values in above equation, we get:

Hence, the amount of time required by iodine gas to effuse is 112.9 seconds.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3