If the density of ocean water at a depth of 1.00 x 104 m is 1.071 g/mL and if 26.0 g of water at that depth contains 182mg of potassium chloride, what is the molarity of potassium chloride in the sample?

Molarity of potassium chloride is 0.100M

Explanation:

Molarity is defined as moles of solute per liter of solvent.

Moles of solute (Potassium chloride; MW: 74.55g/mol):

0.182g × (1mol / 74.55g) = 2.44x10⁻³mol KCl

Liters of water using density are:

26.0g Water × ( 1mL / 1.071g) × (1L / 1000mL) = 0.0243L

Thus, molarity of KCl in the sample is:

2.44x10⁻³mol KCl / 0.0243L = 0.100M

I hope it helps!

Explanation:

Below is an attachment containing the solution.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

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i think that is the right