Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibrium described by the equation N2O4(g) 2NO2(g) If at equilibrium the N2O4 is 39% dissociated, what is the value of the equilibrium constant, Kc, for the reaction under these conditions

The value of equilibrium constant is 0.997

Explanation:

We are given:

Percent degree of dissociation = 39 %

Degree of dissociation, = 0.39

Concentration of , c =

The given chemical equation follows:

Initial:                c             -

At Eqllm:              

So, equilibrium concentration of

Equilibrium concentration of

The expression of for above equation follows:

Putting values in above equation, we get:

Hence, the value of equilibrium constant is 0.997

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates