What is the change in enthalpy associated with the combustion of 530 g of methane (CH4)?Report your answer in scientific notation. Your answer should have two significant figures. Use −890.8kJmol for the molar heat of combustion of methane.

-2.9 X 10^4 kJ

Explanation:

First, calculate the number of moles of CH4 using a formula mass of 16.043gmol from the periodic table.

530g × 1.0 mol /16.043g = 33.036 mol

Next, calculate the total change in enthalpy.

ΔH = 33.036 mol × −890.8kJ/mol = −29,428kJ

The answer should have two significant figures, so round to −2.9 × 10^4 kJ.

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