The gas left in a used aerosol can is at a pressure of 103 kPa at 25.0 °C. If the can heats up to 50.0 °C, what is the pressure of the gas inside the can, assuming the volume of the can is constant? A. 112 kPa B. 211 kPa C. 415 kPa D. 541 kPa

A.

112 kPa

Explanation:

We’ll use the combined gas law equation;

P₁V₁/T₁ = P₂V₂/T₂

Because the volume of the gas remains the same, then the V₁ and V₂ cancel out leaving us with;

P₁/T₁ = P₂/T₂

We can now replace the variables with the values given in the question. Remember to convert the temperatures to Kelvin;

25 degrees C = 298.15 K

50 degrees C = 323.15 K

103/298.15 = P₂/323.15

103/298.15 * 323.15 = P₂

111.63659 = P₂

= 112 kPa

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

answerlinnaeus;