Using periodic trends, place the following bonds in order of increasing ionic character. Si-P Si-Cl Si-S Using periodic trends, place the following bonds in order of increasing ionic character. Si-P Si-Cl Si-S Si-S < Si-Cl < Si-P Si-Cl < Si-S < Si-P Si-Cl < Si-P < Si-S Si-P < Si-Cl < Si-S Si-P < Si-S < Si-Cl

Option (5) is the correct answer.

Explanation:

An ionic bond is formed by transfer of electrons between the two chemically combining atoms. Whereas a covalent bond is defined as the bond formed by sharing of electrons between the two chemically combining atoms.

When electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.7 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.7 or greater than the bond formed is ionic in nature.

Therefore, electronegativity difference of the given species is as follows.

Si-P = 2.1 - 1.8 = 0.3

Si-Cl = 3.0 - 1.8 = 1.2

Si-S = 2.5 - 1.8 = 0.7

Thus, we can conclude that given bonds are placed in order of increasing ionic character as follows.

                           Si-P < Si-S < Si-Cl

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.