How many grams of o2(g) are needed to completely burn 94.4 g of c3h8(g)?

Molar mass:

O₂ = 16 x 2 = 32.0 g/mol    

C₃H₈ = 12 x 3 + 1 x 8 = 44.0  g/mol

Balancing chemical equation :

C₃H₈+ 5 O₂ = 3 CO₂ + 4 H₂O

44.0 g C₃H₈ 5 x 32.0 g O₂
94.4 g C₃H₈ ( mass of O₂)

mass of O₂ = 94.4 x 5 x 32.0 / 44

mass of O₂ = 15104 / 44

= 343.27 g of O₂

hope this helps!

Its strengthits conductivity of heat and electricity its shiny colourmalleable and ductility

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.