Chemistry, 11.03.2020 04:47 kingbolt1

The elementary reaction 2H20(g)<--->2H2(g)+O2(g) proceeds at a certain temperature until the partial pressures of H2O, H2, and O2 reach 0.0900 atm, 0.00450 atm, and 0.00100 atm, respectively. What is the value of the equilibrium constant at this temperature?

Answers: 3

Show answers

Answers

Answer from: ijohnh14

Answer : The value of equilibrium constant (Kp) is, $2.5\times 10^{-6}$

Explanation : Given,

Partial pressure of H_2O = 0.0900 atm

Partial pressure of H_2 = 0.00450 atm

Partial pressure of O_2 = 0.00100 atm

The given chemical reaction is:

$2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$

The expression for equilibrium constant is:

$K_p=\frac{(p_{H_2})^2\times (p_{O_2})}{(p_{H_2O})^2}$

Now put all the given values in this expression, we get:

$K_p=\frac{(0.00450)^2\times (0.00100)}{(0.0900)^2}$

$K_p=2.5\times 10^{-6}$

Thus, the value of equilibrium constant (Kp) is, $2.5\times 10^{-6}$

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

in scientific notation, the value of the speed of light in a vacuum

will be written as 2.995 * 10^8. when this value is represented in the form of

a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

Another question on Chemistry

Chemistry, 22.06.2019 11:00

What is the temperature of 0.750 mol of a gas stored in a 6,850 ml cylinder at 2.21 atm? . 2.95 k 5.24 k 138 k 246 k

Answers: 3

Answer

Chemistry, 22.06.2019 11:00

Which are examples of how technology has advanced scientific understanding.1using hot water to sterilize medical equipment.2transplanting a human organ into another individual.3inserting genes from one sheep into another cell to make a cloneunderstanding the different structures that make up a cell.4examining microorganisms from the deepest parts of the ocean

Answers: 2

Answer

Chemistry, 22.06.2019 11:00

What can be found in the ionosphere

Answers: 1

Answer

Chemistry, 22.06.2019 12:00

Consider the following reaction at equilibrium. 2co2 (g) 2co (g) + o2 (g) h° = -514 kj le châtelier's principle predicts that the equilibrium partial pressure of co (g) can be maximized by carrying out the reaction a. at high temperature and high pressure b. at high temperature and low pressure c. at low temperature and low pressure d. at low temperature and high pressure e. in the presence of solid carbon

Answers: 2

Answer

You know the right answer?

The elementary reaction 2H20(g)<--->2H2(g)+O2(g) proceeds at a certain temperature until the p...

Questions