How many particles are there in 1.43 g of a molecular compound with a gram molecular mass of 233 g?

3.7× 10²¹particles

Explanation:

Given data:

Mass of compound = 1.43 g

Gram molecular mass = 233 g

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For 1.43 g of compound:

one mole =  6.022 × 10²³ particles

1.43 g × 6.022 × 10²³ particles  / 233 g

0.037× 10²³ particles

3.7× 10²¹particles

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.