What is the mass of 8.83 × 10 ^23 formula units of iron (III) oxide, Fe2O3?

234.68g

Explanation:

We understood from Avogadro's hypothesis that 1mole of any substance contains 6.02x10^23 atoms. Therefore, 1mole of Fe2O3 also contains 6.02x10^23 atoms

1 mole of Fe2O3 = (56x2) + (16x3) = 112 + 48 = 160g

Now, if 160g of Fe2O3 contains 6.02x10^23 atoms,

Therefore Xg of Fe2O3 will contain 8.83×10^23 atoms i.e

Xg of Fe2O3 = (160x8.83×10^23)/6.02x10^23 = 234.68g

2b2t

explanation:

2b2t

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol