What is the oxidation number of each atom in sodium hydrogen carbonate

Oxidation number of each atom in sodium hydrogen carbonate ( NaHCO3) are

Na = +1

H = +1

C = +4

O = -2

Explanation:

Let's pick the first atom

NaHCO3

find oxidation number of Na

Na + 1 +4 + 3(-2) = 0( because there is no charge)

Na + 5 - 6 = 0

Na = 6 -5

Na = +1

Always put the sign

Find the oxidation number of H in NaHCO3

+1 + H + 4 + 3(-2) = 0.

H + 1 + 4 + 3(-2) = 0

H + 5 -6 = 0

H = 6 -5

H = +1

Find the oxidation number of C In NaHCO3

+1 +1 +C + 3(-2) = 0

C + 1+1-6 = 0

C +2 - 6= 0

C = 6 -2

C = +4

Find the oxidation number of O in NaHCO3

+1 + 1 + 4 + 3(O) = 0

6 + 3 (O) = 0

3(O) = -6

Divide through by 3 to get O

3(O) / 3 = -6 / 3

O = -6/3

O = -2

the ratio of the conjugate base to the acid required to attain the desired ph.

there are two significant figures.