At what substrate concentration would an enzyme with a Km of 0.0050 M operate at one-eighth of its maximum rate?

7.14x10⁻⁴ M

Explanation:

To calculate the concentration of the enzyme we need to use the Michaelis–Menten equation:

Where:

v: is the reaction rate of the reaction

Vmax: is the maximum rate achieved by the system

[S]: is the concentration of the substrate

Km: is the Michaelis constant

Having that:

v = Vmax/8 and Km = 0.0050 M

The concentration of the enzyme is:

Therefore, the concentration of the enzyme is 7.14x10⁻⁴ M.

I hope it helps you!