A specimen of aluminum having a rectangular cross-section of 10 mm x 12.7 mm is pulled in tension with 35,500 N of force, producing only elastic deformation. Calculate the resulting strain.

Explanation:

The given data is as follows.

            Cross-section area of the rectangular is as follows.

      Area =

              =

              =

Tension applied on the specimen is 35,500 N

Now, formula to calculate the modulus of elasticity for a material of aluminium is as follows.

       E = 70 GPa

          =

or,      =

Now, stress on the specimen is as follows.

                      =

                      =

According to Hook's law, we will calculate the resulting stain as follows.

                  =

                  =

Thus, we can conclude that the resulting strain is .

answer

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