Observe the reaction between N2 and H2 to make NH3.
N2(g) + H2(g) → NH3(g)
If 2 molecules of N2 react with 3 molecules of H2 , determine the number of molecules of NH3 that could form from each starting material.

, 4 molecules of ammonia, NH3(g) is produced; 2 molecules of ammonia, NH3(g) is produced respectively

Explanation:

The balanced equation is stated below N2(g) + 3H2(g) → 2NH3(g)

1 mole of N2(g) reacts with 3 moles of H2(g) to yield 2 moles of NH3(g)

1) If 2 molecules of N2 react, then the balanced equation will be

2N2(g) + 6H2(g) → 4NH3(g)

Thus, 4 molecules of ammonia, NH3(g) is produced

2) If 3 molecules of H2 react, then the balanced equation will be

N2(g) + 3H2(g) → 2NH3(g)

Thus, 2 molecules of ammonia, NH3(g) is produced

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.