A balloon has a pressure of 104.5 kpa and a volume of 3.4L. If the pressure is reduced to 42.7 kpa, what will the volume change to?

The answer to your question is 8,32 L

Explanation:

Data

Pressure 1 = 104.5 kPa

Volume 1 = 3.4 L

Pressure 2 = 42.7 kPa

Volume 2 = ?

Formula

- To solve this problem use the Boyle's law.

       P1V1 = P2V2

- Solve for V2

       V2 = P1V1 / P2

- Substitution

       V2 = (104.5)(3.4) / 42.7

-Simplification

       V2 = 355.3 / 42.7

- Result

        V2 = 8.32 L            

The new volume is 8.3 L

Explanation:

Step 1: Data given

Initial pressure of balloon = 104.5 kPa = 1.0313348 atm

Volume of the balloon is 3.4 L

The pressure is reduced to 42.7 kPa = 0.4214162 atm

Step 2: Calculate the new volume

p1*V1 = p2 *V2

⇒p1 = the initial pressure in the balloon = 1.0313348 atm

⇒V1 = the initial volume = 3.4 L

⇒p2 = the reduced pressure = 0.4214162 atm

⇒V2 = the new volume

1.0313348 atm * 3.4 L = 0.4214162 * V2

V2 = 8.3 L

The new volume is 8.3 L

answer: i would say b.

explanation: