An aqueous solution of iron(II) sulfate (FeSO4) is prepared by dissolving 2.75 g in sufficient deionized water to form a 150.00 mL solution. Calculate the molarity of the solution.

The molarity of iron(II) sulfate solution is 0.724 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of iron(II) sulfate = 2.75 g

Molar mass of iron(II) sulfate = 152 g/mol

Volume of solution = 150.0 mL

Putting values in above equation, we get:

Hence, the molarity of iron(II) sulfate solution is 0.724 M

the answers would be

the first one and the second one