A 7.65L holds 0.99 mol of oxygen gas at 35.55 degrees celsius. what is the pressure

3.27atm

Explanation:

The following were obtained from the question:

V = 7.65L

n = 0.99 mol

T = 35.55°C = 35.55 +273 = 308.55K

R = 0.082atm.L/K.mol

P =

PV = nRT

P = nRT/V

P = (0.99 x 0.082 x 308.55)/7.65

P = 3.27atm

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

0.88m hope i am correct : )