Consider the following scenario: 4.000 g of solid, reagent grade NaOH was dissolved in enough water to make 1.00 L of solution. What is the calculated molarity of the solution? The formula weight of NaOH is 40.0 g/mol. a. 0.100 M b. 10.0 M c. 1.00 x 10-2 M d. 1.00 M How will the actual molarity of the NaOH solution from the previous question compare to the calculated molarity?

that tool would be a compass

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.