The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H 2 O that can be produced by combining 65.8 g of each reactant? 4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )

44.5 g of will be produced from the given masses of both reactants.

Explanation:

To calculate the moles :

According to stoichiometry :

5 moles of require 4 moles of

Thus 2.06 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 5 moles of give = 6 moles of

Thus 2.06 moles of give =  of

Mass of

Thus 44.5 g of will be produced from the given masses of both reactants.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

gasoline is a mixture. it contains several different kinds of compounds that can be present in a variety of ratios.