Chemistry, 13.03.2020 18:34 chloeann5397

Aspirin is prepared by reaction of salicylic acid (C7H6O3) with acetic anhydride (C4H6O3)according to the following equation:
C7H6O3Salicylicacid+C4H6O3Aceticanh ydride→C9H8O4Aspirin+CH3COOHAcetica cid

a. How many grams of acetic anhydride are needed to react with 3.07 g of salicylic acid?
b. How many grams of aspirin will result?
c. How many grams of acetic acid are formed as a by-product?

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Answer from: cookiebrain72

For a: The mass of acetic anhydride reacts is 2.25 grams

For b: The mass of aspirin produced is 3.96 grams

For c: The mass of acetic acid produced is 1.32 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of salicylic acid = 3.07 g

Molar mass of salicylic acid = 138.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of salicylic acid}=\frac{3.07g}{138.12g/mol}=0.022mol$

The chemical equation for the reaction of salicylic acid and acetic anhydride follows:

$C_7H_6O_3+C_4H_6O_3\rightarrow C_9H_8O_4+CH_3COOH$

For a:

By Stoichiometry of the reaction:

1 mole of salicylic acid reacts with 1 mole of acetic anhydride

So, 0.022 moles of salicylic acid will react with = $\frac{1}{1}\times 0.022=0.022mol$ of acetic anhydride

Now, calculating the mass of acetic anhydride from equation 1, we get:

Molar mass of acetic anhydride = 102.1 g/mol

Moles of acetic anhydride = 0.022 moles

Putting values in equation 1, we get:

$0.022mol=\frac{\text{Mass of acetic anhydride}}{102.1g/mol}\\\\\text{Mass of acetic anhydride}=(0.022mol\times 102.1g/mol)=2.25g$

Hence, the mass of acetic anhydride reacts is 2.25 grams

For b:

By Stoichiometry of the reaction:

1 mole of salicylic acid produces 1 mole of aspirin

So, 0.022 moles of salicylic acid will produce = $\frac{1}{1}\times 0.022=0.022mol$ of aspirin

Now, calculating the mass of aspirin from equation 1, we get:

Molar mass of aspirin = 180.16 g/mol

Moles of aspirin = 0.022 moles

Putting values in equation 1, we get:

$0.022mol=\frac{\text{Mass of aspirin}}{180.16g/mol}\\\\\text{Mass of aspirin}=(0.022mol\times 180.16g/mol)=3.96g$

Hence, the mass of aspirin produced is 3.96 grams

For c:

By Stoichiometry of the reaction:

1 mole of salicylic acid produces 1 mole of acetic acid

So, 0.022 moles of salicylic acid will produce = $\frac{1}{1}\times 0.022=0.022mol$ of acetic acid

Now, calculating the mass of acetic acid from equation 1, we get:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.022 moles

Putting values in equation 1, we get:

$0.022mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.022mol\times 60g/mol)=1.32g$

Hence, the mass of acetic acid produced is 1.32 grams

Answer from: Quest

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

Answer from: Quest

tracks, burrows, eggshells, nests, tooth marks, or gastroliths

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Aspirin is prepared by reaction of salicylic acid (C7H6O3) with acetic anhydride (C4H6O3)according t...

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