A current is passed through a Ga(NO3)3 solution for 1.5 hours, and after this time period the mass of metal produced was 6.3 grams. What is the current, in amperes, that is required to produce such an amount of gallium?
Choose 1

A. 1.7
B. 5.0
C. 100
D. 300

Option B. 5.0

Explanation:

Gallium is a trivalent metal as such it will require 3 faraday to deposit its metal according to the equation below:

Ga^3+ + 3e- —> Ga

1 faraday = 96500C

3 faraday = 3 x 96500C = 289500C

From the equation above,

70g of Ga was deposited by 289500C.

Therefore 6.3g of Ga will be deposited by = (6.3 x 289500)/6.3 = 26055C

Now, we can calculate the current flowing through the solution as follows:

t = 1.5 hrs = 1.5 x 3600 = 5400secs

Q = 26055C

I =?

Q = It

I = Q/t

I = 26055/5400

I = 5A

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