Write the balanced equation for the reaction of acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3). What type of reaction(s) took place?
Please Provide an Explanation. Thank-you!

1. CH3COOH + NaHCO3 —> CH3COONa + H2O + CO2

2. Double Displacement and Decomposition reaction.

Explanation:

1. The balanced equation for the reaction is given below:

CH3COOH + NaHCO3 —> CH3COONa + H2O + CO2

2. There are actually two types of reactions that occur in the reaction between acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3)

The first is a DOUBLE DISPLACEMENT reaction in which the acetic acid react with the bicarbonate to form sodium acetate and carbonic acid as shown below:

CH3COOH + NaHCO3 —> CH3COONa + H2CO3

The second type of reaction is DECOMPOSITION REACTION. The carbonic acid (H2CO3) form is unstable and will decompose to form H2O and CO2 as shown below:

H2CO3 —> H2O + CO2