Aballoon containing 0.500 mol ar at 0.00°c and 65.0 kpa pressure is expanded by adding more argon. how many moles of argon are added to bring the sample to a final volume of 60.0 l at 30.0°c and 45.0 kpa?

what is the original volume of the gas?

Use the ideal gas equation.

PV = nRT

1) Volume of the original gas

V = nRT/P = [0.5mol * 0.082 atm-l/mol-K * 273.15K] / 0.6415 atm] = 17.45 l

2) # of mols to bring to the new state

n = PV/RT = [0.444 atm * 60 l] / [0.082 atm-l/k-mol *303.15k] = 1.07 mol

Then, 1.07 mol - 0.5mol = 0.57 mol were added.