Calculate the standard entropy change for the following reaction cu(s) + 1/2 O2(g) —> cuo(s)

The study of chemicals and bonds is called chemistry.

The correct answer to the question is -93.12 J/K.mol

The Standard entropy change is stated as follows:-

Δ

Δ

Δ

Δ

Δ

Hence, the correct answer is -93.12j/K.mol

For more information, about the entropy, refer to the link:-

link

The standard entropy change for the reaction -93.12 J/K.mol

Explanation:

The Standard entropy change:

ΔS° = [42.59] - [33.17 + (205.07/2)] J/K.mol

ΔS° = [42.59] - [33.17 + 102.535] J/K.mol

ΔS° = [42.59] - [135.705] J/K.mol

ΔS° = - 93.12 J/K.mol