A bottle of commercial vinegar contains 5% acetic acid, ch3cooh, by volume (95% water). the density of acetic acid is 1.05 g/ml and water is 1.00 g/ml. from this data calculate the concentration of acetic acid in vinegar in: molality, molarity, parts by mass, and the mole fraction.

See explanation.

Explanation:

Hello,

For this exercise, it is convenient to assume a basis of 5 g of acetic acid which is the solute and 95 g of water which is the solvent, in such a way, one proceeds as follows:

(a) Molarity:

Thus:

(b) Molality:

In this case, the moles were already computed and the mass of the solvent is in kilograms, thus:

(c) Parts by mass:

(d) Mole fraction:

In this case, the moles of water are required:

Since:

Best regards.

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms