A child has a toy balloon with a volume of 1.80 L. The temperature of the balloon when it was filled was 293 K at a pressure of 101.3 kPa. If the child were to let go of the balloon and it rose 3 kilometers into the sky where the pressure of 67.6 kPa and the temperature is 263 K, what would the new volume of the balloon be?

2.42L

Explanation:

Given parameters:

V₁  = 1.8L

T₁ = 293K

P₁  = 101.3kPa

P₂ = 67.6kPa

T₂  = 263K

Unknown:

V₂ = ?

Solution:

To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;

All the units are in the appropriate form. We just substitute and solve for the unknown;

         101.3 x 1.8 / 293    =     67.6 x V₂  /  263

          V₂   = 2.42L

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.