A chemist prepares a solution of vanadium chloride by measuring out of into a volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution. Be sure your answer is rounded to significant digits.

The question is incomplete, the complete question is:

A chemist prepares a solution of vanadium (III) chloride (VCl3) by measuring out 0.40g of VCl3 into a 50.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution. Be sure your answer is rounded to the correct number of significant digits.

0.153M of anions

Explanation:

First we calculate the concentration of the solution. From m/M= CV

m=given mass, M= molar mass, C =concentration of solution, V= volume of solution

Molar mass of compound= 51 + 3(35.5)= 157.5gmol-1

0.4g/157.5gmol-1= C×50/1000

C= 2.54×10-3/0.05= 0.051M

But 1 mole of VCl3 contains 3 moles of anions

Therefore, 0.051M will contain 3×0.051M of anions= 0.153M of anions

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