What is the percent composition of each of the elements in Al(OH) 3 ?

%Al = 34.6%

%0 = 61.5%

%H = 3.9%

Explanation:

Al(OH)3

Atomic mass of Aluminum Al = 27

Atomic mass of Oxygen O=16

Atomic mass of Hydrogen H=1

Molar mass of Al(OH)3 = 27 + (16*3) + (1*3)

Al(OH)3 = 27 + 48 + 3

Al(OH)3 = 78

Percentage composition;

Aluminum Al= (27/78) × 100

Aluminum Al=0.346 × 100 =34.6%

Oxygen O=(16*3/78) × 100

Oxygen O= 0.615 × 100 =61.5%

Hydrogen H= (1*3/78) × 100

Hydrogen H=0.039 × 100=3.9%

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms