A compound has the empirical formula CH2O. If its molar mass is 150 g/mol, what is the molecular formula of the compound?

The molecular formula of the compound that has a molar mass of 150g/mol and an empirical formula of CH2O is C5H10O5

HOW TO CALCULATE MOLECULAR FORMULA:

(CH20)n = 150g/mol

{12 + 1(2) + 16}n = 150

(12 + 2 + 16)n = 150

30n = 150

n = 150 ÷ 30

n = 5

= (CH2O)5

= C5H10O5

Learn more at: link

C5H10O5

Explanation:

The molecular formula is a multiple of the empirical formula. I.e

Molecular formula => [CH2O]n

[CH2O]n = 150

[12 + (2x1) + 16 ]n = 150

30n = 150

Divide both side by the coefficient of n i.e 30

n = 150/30 = 5

Molecular formula => [CH2O]n

Molecular formula => [CH2O]5

Molecular formula => C5H10O5

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.