Consider the following reaction: Mn(s) + CuSO4(aq) → MnSO4(aq) + Cu(s) Which of the following statements regarding this reaction is correct?
Manganese is neither oxidized nor reduced.
Copper is the reducing agent.
Each copper gains two electrons.
Manganese is the oxidizing agent.
The sulfate ion is oxidized.
I need help asap please and thank you

Each copper gains two electrons

Explanation:

Chemical equation:

CuSO₄(aq) + Mn(s)   →  MnSO₄(aq)  + Cu(s)

This is single replacement reaction. The reactivity of manganese is higher than copper that's why Manganese replace the copper and react with sulfate to form copper sulfate.

Copper gains two electrons and gets reduced. The oxidation state of copper on left side is +2 while on right side its 0 so it gain two electrons and gets reduced.

while oxidation state of manganese on left side is 0 while on right side its +2. It means Mn lose to electrons and gets oxidized.

So  copper is oxidizing agent while manganese is reducing agent.

while the oxidation state of sulfate is not changed.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.