A solution prepared by mixing 10 ml of 1 m hcl and 10 ml of 1.2 m naoh has a ph of

The mixing of the two components is known as a solution. The components are as follow:-

The Ph of the solution will be 13. The solution is as follows:-

All the data are given in question, therefore the molarity and the molality of the solution are 0.01M and 0.012m.

When acid reacts with the base it makes salt and this process is known as neutralization. The effects of acid neutralized by the base.

Hence, the amount of H+ and OH- will be the same in the solution.

After solving the equation.

The PH of the solution is

Hence, the ph of the solution is 13

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pH of resulting solution will be 13

Explanation:

pH is the measure of acidity or alkalinity of a solution.

Moles of ion =

Moles of ion =

For neutralization:

1 mole of ion will react with 1 mole of ion

0.01 mol of  ion will react with = of ion

Thus (0.012-0.01)= 0.002 moles of are left in 20 ml or 0.02 L of solution.

Thus the pH of resulting solution will be 13

the first point, i am pretty sure.

the answer for sodium is 0.186

the answer for rubidium is 0.251